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BigorU [14]
3 years ago
10

First to answer right gets brainliest!!! You are making a mosaic design on a square table top. You have already covered half of

the table top with 150 1-inch square tile pieces.
A. What are the dimensions of the table top?

B. What is the measure of the diagonal from one corner to the opposite corner of the table top?
Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

i don't know

Step-by-step explanation:

You might be interested in
-3 multiplied by 8.2
bekas [8.4K]

Answer:

-24.6

Step-by-step explanation:

-3*8.2= -24.6

8 0
3 years ago
Read 2 more answers
I can't find this answer
Julli [10]
The answer I think is C
3 0
3 years ago
The function f is defined by f(x)=2.1x−1.7. Use this formula to find the following values of f. f(x+2)
Yuki888 [10]

The value of f(x+2)=2.1x+2.5

Step-by-step explanation:

Given: The function f(x)=2.1x-1.7

Using this formula, we need to find the value of f(x+2)

Hence, we need to substitute x by x+2 to find the value of f(x+2)

f(x+2)=2.1(x+2)-1.7

Multiplying the term (x+2) by 2.1, we get,

f(x+2)=2.1x+4.2-1.7

Adding the constant term,

f(x+2)=2.1x+2.5

Thus, the value of f(x+2) is f(x+2)=2.1x+2.5

8 0
3 years ago
5/2=? ?/? ill give brainliest
adoni [48]

Answer:

Okay so you jsut gotta divide

5/2 is basically saying 5 divided by 2, the bar basically means divide by.

Now 5/2 is 2.5

2.5 into a mixes is 2 1/2

7 0
2 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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