Answer:
Play 3
Step-by-step explanation:
Given:
![\left\begin{array}{ccccc}{Play}&{1}&{2}&{3}&{4}&{Yards}&{+4}&{-6}&{-2}&{+3}\end{array}\right](https://tex.z-dn.net/?f=%5Cleft%5Cbegin%7Barray%7D%7Bccccc%7D%7BPlay%7D%26%7B1%7D%26%7B2%7D%26%7B3%7D%26%7B4%7D%26%7BYards%7D%26%7B%2B4%7D%26%7B-6%7D%26%7B-2%7D%26%7B%2B3%7D%5Cend%7Barray%7D%5Cright)
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
Its B, cause it’s collinear
The answer is 3
because 18/27 = 2/3