Answer:
Byzantine war and world war II
Explanation:
Answer:
Molarity = 0.4 mol.L⁻¹
Solution:
Molarity is given as,
Molarity = Moles / Volume of Solution
Also,
Moles = Mass / M.mass
So,
Molarity = Mass / (M.mass × Volume of Solution)
Data Given,
Mass = 89 g
M.mass of Na₂SO₄ = 142 g.mol⁻¹
Volume = 1.5 L
Putting Values,
Molarity = 85 g ÷ (142 g.mol⁻¹ × 1.5 L)
Molarity = 0.399 ≈ 0.4 mol.L⁻¹
of oxygen at STP would be required to react completely with 38.8g of propane.
<u>Given that :</u>
molar mass of propane = 44 g/mol
mass of propane = 38.8 g
∴ Moles present in 38.8 g of propane = = 0.88 mole
<u>applying rule of balanced equations </u>
1 mole of propane = 5 moles of oxygen
0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen
Note : volume of 1 mole of oxygen at STP =
∴Total volume of oxygen required at STP = 22.4 * 4.4 =
Hence we can conclude that the volume of oxygen at STP required to react completely
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Answer: Amount of volume needed in Litres is 0.09L
Explanation:
Given that the concentration in Mol/L =3.67M
Mass of K2SO4 = 57.3g
Molar mass of K2SO4 = 174.01g/mol
From stochiometry,
Mole = Mass/Molar mass
Mole = 57.3/174.01= 0.33mol.
Concentration in mol/L=
Mole/volume
3.67=0.33/volume
Volume= 0.33/3.67
Volume = 0.09L
Therefore the volume of K2SO4 needed is 0.09L