How many liters of a 3.67 M K2SO4 solution are needed to provide 57.3 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equi
valent to mol/L.
1 answer:
Answer: Amount of volume needed in Litres is 0.09L
Explanation:
Given that the concentration in Mol/L =3.67M
Mass of K2SO4 = 57.3g
Molar mass of K2SO4 = 174.01g/mol
From stochiometry,
Mole = Mass/Molar mass
Mole = 57.3/174.01= 0.33mol.
Concentration in mol/L=
Mole/volume
3.67=0.33/volume
Volume= 0.33/3.67
Volume = 0.09L
Therefore the volume of K2SO4 needed is 0.09L
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