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blagie [28]
3 years ago
15

How many liters of a 3.67 M K2SO4 solution are needed to provide 57.3 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equi

valent to mol/L.
Chemistry
1 answer:
WITCHER [35]3 years ago
7 0

Answer: Amount of volume needed in Litres is 0.09L

Explanation:

Given that the concentration in Mol/L =3.67M

Mass of K2SO4 = 57.3g

Molar mass of K2SO4 = 174.01g/mol

From stochiometry,

Mole = Mass/Molar mass

Mole = 57.3/174.01= 0.33mol.

Concentration in mol/L=

Mole/volume

3.67=0.33/volume

Volume= 0.33/3.67

Volume = 0.09L

Therefore the volume of K2SO4 needed is 0.09L

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Marrrta [24]

Answer: a compound is a chemically made or chemically bonded where as a mixture is just something added like a smoothie

6 0
2 years ago
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What is the pH of a solution with a concentration of 4.7 × 10-4 molar H3O+?
wlad13 [49]
The pH of a liquid substance is calculated through the equation,
                                       pH = -log[H3O+]
Substituting the given concentration of the hydronium ion to the equation above,
                                        pH = -log[4.7x10^-4 M]
The value of pH is equal to 3.33. Thus, the pH of the solution is approximately 3.33. 
3 0
3 years ago
Given: 4Na + O2 → 2Na2O In this chemical reaction, how many moles of Na2O will be produced if 2.90 moles of Na react completely?
crimeas [40]

Since we already have the balanced equation, we know that the ratio between Na:Na_{2}O is 4:2 respectively.

So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:

\frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}}

Then we cross multiply and solve for x:

4x=5.8

x=1.45

Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of Na_{2}O that are produced.

3 0
2 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
CaCO3 For each of the following compounds, decide whether the compound's solubility in aqueous solution changes with pH. If the
Slav-nsk [51]

Answer:

Hello attached below is the data found in Aleks Data tab

answer :

i) N0

ii) N0

iii) YES ,  pH of highest solubility = 5

Explanation:

i) For CuBr

solubility does not change with pH  hence answer = NO

ii) For MgCl2

solubility does not change with pH hence the answer = NO

iii) For Ba(OH) 2

Solubility does change with pH hence the answer = YES

and the pH at which the highest solubility will occur is = 5

attached below is the reason for the answers given

4 0
3 years ago
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