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MrMuchimi
4 years ago
7

What two wars hurt russia

Chemistry
1 answer:
saw5 [17]4 years ago
7 0

Answer:

Byzantine war and world war II

Explanation:

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Would the concentration of hydroxide ion in a 0.30 m solution of potassium hydroxide (koh) be greater than, less than, or equal
patriot [66]

Potassium hydroxide KOH is a strong base which can completely ionize to form potassium and hydroxide ions.

The equation representing ionization of KOH,

KOH(aq)-->K^{+}(aq)+OH^{-}(aq)

The mole ratio of hydroxide to KOH from the above equation is \frac{1molOH^{-} }{1molKOH}

The given concentration of KOH solution=0.30M

Calculating the concentration of hydroxide ions present in 0.30M KOH solution:

\frac{0.30mol KOH}{L} *\frac{1mol OH^{-} }{1 mol KOH} =0.30\frac{mol}{L}OH^{-}

Therefore the concentration of hydroxide ion will be equal to 0.30 M in a 0.30 M KOH solution.

6 0
4 years ago
Which is the outmost layer of the atmosphere
ikadub [295]

Answer: Exosphere

Explanation: Exosphere. This is the outermost layer of the atmosphere. It extends from the top of the thermosphere to 6,200 miles (10,000 km ) above the earth.

4 0
3 years ago
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All atoms of an element are ___________.
nignag [31]
My answer would be B there you go

5 0
3 years ago
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How do you think Oxygen can be in the crust when it is a gas at room temperature in the atmosphere?
otez555 [7]

Answer: Through diffusion

Explanation:

Oxygen can be defined as the most abundant element on earth. It is a gas at room temperature. It becomes the part of the earth crust by the process of diffusion.

Diffusion is a process of movement of molecules from a region of high concentration to the low concentration. The oxygen remains in high concentration in the atmosphere diffuses into earth crust at low concentration.

5 0
3 years ago
Gasoline has a density of 0.7197 grams per milliliter. Calculate the mass, in grams, of a sample of gasoline with a volume of 48
barxatty [35]

Answer:

34.9103 or 34.9 g

Explanation:

Remember Density is a broken heart: m/v.

In this scenario (Let x = # of grams in the sample of gasoline),

D = 0.7198 g/mL = x g / 48.5 mL

So,

(0.7198 g/mL) * (48.5 mL) = x g

x g = 34.9103 = 34.9 g (Accounting for Significant Figures)

8 0
2 years ago
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