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SCORPION-xisa [38]
3 years ago
13

if a watch was sold for Rs 1656 after allowing 10% discount on the marked price and adding 15% VAT .find discount amount​

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0
Answer: Sp+vat=1656 1656=spx 115/100 sp=1656xloo/115=1440 mp = spx loo/100-Disc = 1440xloo/90=1600.
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If 8(a + b) = 48, what is the value of a + b?
Cloud [144]

Answer:

8(a + b) = 48 \\  \\ a + b =  \frac{48}{8}  \\  \\ a + b = 6

I hope I helped you^_^

5 0
3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
The sides of a square are five to the power of two fifths inches long. What is the area of the square?
Feliz [49]
I believe the correct answer from the choices listed above is the first option. If the  sides of a square are five to the power of two fifths inches long, then the are of the square would be <span>five to the power of four fifths square inches. Hope this answers the question.</span>
3 0
3 years ago
A square with an area A2 of is enlarged to a square with an area of 25A2. How was the side of the smaller square changed?
makvit [3.9K]
Given:
a square with an area of a² is enlarged to a square with an area of 25a².

The side length of the smaller square was changed when The side length was multiplied by 5.

Area = (1a)² = a²
Area = 1a * 5 = 5a ⇒ (5a)² = 25a²
3 0
3 years ago
Read 2 more answers
Pre calculus, trigonometry Given point M the ordered pair 6 times the square root of 3 comma negative 6 comma which is located o
Nikitich [7]

The possible form of the point (6√3, - 6) in polar form are (r₁, θ₁) = (12, 11π / 6), (r₂, θ₂) = (12, - π / 6).

<h3>How to derive the polar form of a point in rectangular form</h3>

In this problem we find a point in rectangular form, that is, a point of the form (x, y). We are asked to find the polar form of the point, that is, a point described by the following expression:

(r, θ)

Where:

  • r - Magnitude
  • θ - Direction, in radians

The magnitude is found by Pythagorean theorem:

r =√(x² + y²)

And the direction of the point is described by the following inverse trigonometric function:

θ = tan⁻¹ (y / x)

If we know that (x, y) = (6√3, - 6), then the point in polar form is:

r = √[(6√3)² + (- 6)²]

r = 12

θ = tan⁻¹ (- 6 / 6√3)

θ = tan⁻¹ (- √3 / 3)

θ = 11π / 6 rad / θ =  - π / 6 rad

There are two possible solutions: (r₁, θ₁) = (12, 11π / 6), (r₂, θ₂) = (12, - π / 6).

To learn more on point in polar form: brainly.com/question/13103661

#SPJ1

7 0
1 year ago
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