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asambeis [7]
2 years ago
8

Have x 50 notes and y N100 notes. There

Mathematics
2 answers:
Illusion [34]2 years ago
5 0

Answer:

hi

Step-by-step explanation:

hi

slava [35]2 years ago
5 0
You need to use simultaneous equations to solve this problem since there are 2 variables.

1. 50x + 100y = 550 (value of the notes x the number of each note)

2. x + y = 8 (the number of each note added).

3. Multiply the second equation by 50 so that it the x variables are the same in both equations. Thus, 50x + 50y = 400.

4. Subtract 50x + 50y = 400 from 50x + 100y = 550.

5. The subtraction results in 50y = 150.

6. Divide by 50. y = 3, so x must equal 5.
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Select two answer choioces
dexar [7]

Answer:

C or 3rd option

Step-by-step explanation:

1/3 - 2/5

15/15 - 6/15

9/15

B is not correct

2/5 - 1/3

this will be a negative answer

6 0
2 years ago
$14.40 for 4.5 pounds of beef
Svetradugi [14.3K]

Answer:

One pound of beef is $3.2

Step-by-step explanation:

14.40 / 4.5

= 3.2

CHECK:

3.2 * 4.5

=14.40

6 0
2 years ago
Read 2 more answers
The largest prime factor of thirty-five is _____. 7 5 9 11
vichka [17]

Answer:

7

Step-by-step explanation:

Since 9 and 11 do not factor 35, they are not the answer.

5 is a factor of 35, but not the largest. So, the answer is 7.

7 0
2 years ago
Read 2 more answers
Urgent help needed fast
Katena32 [7]

Answer:

Below

Step-by-step explanation:

You can use this formula to find the sum of an arithmetic series

     Sn = n / 2 (a1 + an)

You need to find the number of terms in each series before using the formula

     Tn = a + (n - 1) d

a) 53 = 5 + (n - 1) 3

      n = 17

Sn = 17 / 2 (5 + 53)

    = 493

b) 98 = 7 + (n - 1) 7

      n = 14

Sn = 14 / 2 (7 + 98)

   = 735

       

c) -102 = 8 + (n - 1) -5

        n = 23

Sn = 23 / 2 (8 + (-102))

   = - 1081

d) 41/3 = 2/3 + (n - 1) 1

        n = 14

Sn = 14 / 2 (2/3 + 41/3)

    = 301 / 3 or 100 1/3  

Hope this helped! Best of luck <3

7 0
2 years ago
Use the Distance Formula to find the distance to the nearest tenth between A(-7, -4) and B(-2, 0).
goldenfox [79]
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41 

the distance is approximately 6.4 units
8 0
2 years ago
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