Here we have a problem of probability, we will find that the probability of landing in heads is M/N = 1/3, then we have:
M + N = 1 + 3 = 4.
Let's see how we got that:
Let's define:
p = probability of landing on tails
q = probability of landing on heads.
The probability of getting at least one tails in 3 tosses is 26/27
This means that the probability of not getting tails in the 3 tosses is:
P = 1 - 26/27 = 1/27
And the case where you do not get any tails in the 3 tosses, means that in all the 3 tosses you got heads.
The probability of getting 3 heads in a row is:
P = q^3 = 1/27
Solving for q, we get:
q = ∛(1/27) = 1/3
Now we want to express q = M/N = 1/3
then we have:
M = 1
N = 3
Now we want to compute M + N = 1 + 3 = 4
If you want to learn more about probability, you can read:
brainly.com/question/24369877
Answer:
(c + 7) ( c - 9)
Step-by-step explanation:
2 trikes (6 wheels) and 47 bikes (94 wheels)
or
4 trikes (12 wheels) and 44 bikes (88 wheels)
or
6 trikes (18 wheels) and 41 bikes (82 wheels)
or
8 trikes (24 wheels) and 38 bikes (76 wheels)
or
10 trikes (30 wheels) and 35 bikes (70 wheels)
As long as you start our with an even number of trikes, you'll find a way to use up all the tires with no remainders.
1999 Team won - 15
2000 Team won - 18
2001 Team won - 20
The 2 from the a and the 4 will reduce to 1/2 and the a's from a^2 and 4a will reduce to a/1 so your answer would be (ab^2)/2
Brainliest is always appreciated !
