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Alexeev081 [22]
3 years ago
10

25 points What is the equation for the line in slope-intercept form

Mathematics
2 answers:
allsm [11]3 years ago
5 0

Answer:

y=8x

Step-by-step explanation:

x=1 y= 8

x=2 y=16

8=m+b

16=2m+b

m=8

y=8x

MaRussiya [10]3 years ago
3 0
Choose 2 coordinates from the line. Let’s pick (0,0) and (2,16)

The equation of a line is on the form y = mx + b where m is the slope and b is the y-intercept.

First let’s find the slope:

m = (y2-y1)/(x2-x1) = (16-0)/(2-0) = 16/2= 8

So we have y = 8x + b

We substitue one of the coordinates to find b. Let’s substitute (0,0)

We get 0 = 0 + b. So b = 0

The equation of the line is y = 8x
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ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of -8x^2y^3 \div xy.

-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}

                    =\frac{-8\times x\times x\times y\times y\times y}{xy}

Taking common term xy outside in the numerator.

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Thus, the quotient of -8x^2y^3 \div xy is -8xy^2.

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Cancel the common terms in both numerator and denominator.

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