Question

What is the solution set?

Answer 1

Step-by-step explanation:

$x \div 4 \leqslant 9 \div x$

$x ^{2} \leqslant 36$

$x {}^{2} - 36 \leqslant 0$

$x {}^{2} { - 6}^{2} \leqslant 0$

$(x + 6)(x - 6) \leqslant 0$

$x \leqslant - 6 \: \: or \: \: \: x \leqslant 6$

$- 6 \geqslant x \leqslant 6$

From the explanation the correct answer is the last one from the question above