What is the square root of 5

Mathematics

1 answer:

zlopas [31]3 years ago

7 0

The square root of 5 is 2.236

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Which graph represents the function f(x)=(x-5)^2+3

hammer [34]

Answer:

Parabola

Step-by-step explanation:

We are given that a function

$f(x)=(x-5)^2+3$

The given function is an equation of parabola along y- axis.

General equation of parabola along y- axis with vertex (h,k) is given by

$(y-k)=(x-h)^2$

$y=(x-h)^2+k$

Compare it with given equation then we get

h=5, k=3

Vertex of given parabola =(5,3)

Substitute x=0 then we get

$f(0)=(0-5)^2+3=28$

y-intercept of parabola is at (0,28).

6 0

3 years ago

Read 2 more answers

If the slope of one of these parallel lines is 1.25, the slope of the other line is ___.

oksian1 [2.3K]

1.25 also bc they are parallel

6 0

3 years ago

The roots of a quadratic equation ax2+bx+c=0 are 1+i 5 and 1−i 5 . Find possible values of a, b and c.

Anarel [89]

Answer:

Step-by-step explanation:

If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots. They are (x - 1 + 5i) and (x - 1 - 5i). Now what you do with those is FOIL them out. Doing that gives you the following:

$x^2-x+5ix-x+1-5i-5ix+5i-25i^2$ (what a mess, huh?)

The good thing is that several of those terms cancel each other out. +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x. That leaves you with:

$x^2-2x-25i^2$

Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1. Making that replacement:

$x^2-2x+25$