Answer:
The center line temperature of the beam is
Solution:
As per the question:
Diameter of the cylinder, D = 0.5 m
Radius of the cylinder, r' =
Temperature,
Initial temperature,
Convection coefficient of heat flow,
Time, t = 46 min
k =
Now,
Biot no. is given by:
Now, Fourier no. is given by:
At ,
Now, using Heisler chart, the temperature of the beam is given by:
Answer:
0.26087 rad/s
Explanation:
mass of the child (m) = 40 kg
velocity (v) = 3 m/s
distance (r) = 1.5 m
moment of inertia (I) = 600 kg.m^{2}
rotational momentum of the child = Iω
where
rotational momentum of the child = Iω = 90 x 2 = 180 kg/s
from the conservation of momentum the initial momentum of the child must be the same as the final momentum of the child
initial momentum of the child = final momentum of the child
180 = (90 + 600) ω
180 = 690 ω
ω = 180 / 690 = 0.26087 rad/s