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3 years ago

In what do electromagnetic waves cause disturbances when they transfer energy?

Physics

2 answers:

Lady_Fox [76]3 years ago

8 0

Answer: B - Both electric and magnetic fields

Explanation: Ap*x verified just did the test and got it correct, answer is right infront of me at the moment

Svetlanka [38]3 years ago

5 0

Answer: B

Explanation: just took the quiz on AP3X

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The volcano olympus mons is an unusual example of the cone type called

enot [183]

A shield volcano i believe. hope this helped

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3 years ago

A Ferris wheel has radius 5.0 m and makes one revolution every 8.0 s with uniform rotation. A person who normally weighs 670 N i

DaniilM [7]

Answer:

The apparent weight of the person as she pass the highest point is $N = 458.8 \ N$

Explanation:

From the question we are told that

The radius of the Ferris wheel is $r = 5.0 \ m$

The period of revolution is $T = 8.0 \ s$

The weight of the person is $W = 670 \ N$

Generally the speed of the wheel is mathematically represented as

$v = \frac{2 \pi r}{T }$

substituting values

$v = \frac{2 * 3.142 * 5}{8 }$

$v = 3.9 3 \ m/s$

The apparent weight (the normal force exerted on her by the bench) at the highest point is mathematically evaluated as

$N = mg - \frac{mv^2}{r}$

Where m is the mass of the person which is mathematically evaluated as

$m = \frac{W}{g}$

substituting values

$m = \frac{670}{9.8}$

$m = 68.37 \ kg$

$N = 68.37 * 9.8 - \frac{68.37 * {3.93}^2}{5}$

$N = 458.8 \ N$

5 0

3 years ago

A specimen of aluminum having a rectangular cross section 9.5 mm × 12.9 mm (0.3740 in. × 0.5079 in.) is pulled in tension with 3

ryzh [129]

Answer:

The resultant strain in the aluminum specimen is $4.14 \times {10^{ - 3}}$

Explanation:

Given that,

Dimension of specimen of aluminium, 9.5 mm × 12.9 mm

Area of cross section of aluminium specimen,

$A=9.5\times 12.9=123.84\times 10^{-6}\ mm^2A=122.55\times 10^{-6}\ m^2$

Tension acting on object, T = 35000 N

The elastic modulus for aluminum is, $E=69\ GPa=69\times 10^9\ Pa$

The stress acting on material is proportional to the strain. Its formula is given by :

$\epsilon=\dfrac{\sigma}{E}$

$\sigma$ is the stress

$\epsilon=\dfrac{F}{EA}\\\epsilon=\dfrac{35000}{69\times 10^9\times 122.5\times 10^{-6}}\\\epsilon=4.14\times 10^{-3}$

Thus, The resultant strain in the aluminum specimen is $4.14 \times {10^{ - 3}}$

5 0

4 years ago

Read 2 more answers

Is this an open or a closed circuit?

ANTONII [103]

Answer:

It is a closed circuit.

6 0

4 years ago

Read 2 more answers

A ball is tossed vertically upwards with a speed of 5.0 m s–1. After how many seconds will the ball return to its initial positi

mezya [45]

Answer:

1.02 seconds

Explanation:

Initial velocity = u = 5 m/s

t = Time taken

s = Displacement travelled = 0

a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)

Equation of motion

$s=ut+\frac{1}{2}at^2\\\Rightarrow 0=5t+\frac{1}{2}-9.81\times t^2\\\Rightarrow 0=5t-4.905t^2\\\Rightarrow 0=t(5-4.905t)\\\Rightarro 0=5-4.905t\\\Rightarrow t=\frac{-5}{-4.905}=1.02\ seconds$

So, time taken to return to its initial position is 1.02 seconds

7 0

4 years ago