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Goshia [24]
3 years ago
12

In what do electromagnetic waves cause disturbances when they transfer energy?

Physics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer: B - Both electric and magnetic fields

Explanation: Ap*x verified just did the test and got it correct, answer is right infront of me at the moment

Svetlanka [38]3 years ago
5 0

Answer: B

Explanation: just took the quiz on AP3X

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How many mL of water would be displaced by 408 g of lead
Natasha2012 [34]
For this, we must know the density of lead. This is 11.36 grams per cubic centimeter. The mass present is 408 grams. Therefore, the volume occupied will be:
408 / 11.36 = 35.9 cubic centimeters. This is the volume of water that will be displaced.
Now, we know that one cubic centimeter is equivalent to one mL. Therefore,
35.9 ml of water will be displaced.
6 0
3 years ago
A long, hollow wire with inner radius a and outer radius b carries a uniform current density J. What is the magnetic field as a
sveta [45]

Answer:

The magnetic field in the region a < r < b is B=\frac{u_{0}I(r^{2}-a^{2})   }{2\pi r(b^{2}-a^{2})  }

Explanation:

If we have the a < r < b. The formula of current is:

J=\frac{I_{total} }{A}

Where:

A = area enclosed by the loop.

Itotal = total current in loop.

J=\frac{I}{\pi b^{2}-\pi  a^{2} }

I_{enclosed} =JA_{enclosed}

I_{enclosed} =\frac{I(\pi r^{2}- \pi a^{2})}{\pi b^{2}-\pi a^{2}  }

If we have the Ampere`s law:

\int\limits^a_b {B} \, ds  =u_{0} I_{enclosed} \\2B\pi r=u_{0} (\frac{I(\pi r^{2}-\pi  ^{2} }{\pi ^{2}-\pi  a^{2} } )\\B=\frac{u_{0}I(r^{2}-a^{2})   }{2\pi r(b^{2}-a^{2})  }

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3 years ago
4 WILL GIVE YOU BRAINLIST
Arisa [49]
The last one, handmade gifts require more of the givers time!
5 0
3 years ago
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A man pushes an 250-N crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with th
mel-nik [20]

Answer:

6495.19 Joule

Explanation:

F = Weight of the crate = 250 N

d = Distance the cart is pushed = 30 m

θ = Angle of inclination = 60°

The weight of the crate will be resloved into two components

Fdsinθ and Fdcosθ

Work done by the force of gravity is

W = Fdsinθ

⇒W = 250×30×sin60

⇒W = 6495.19 Joule

∴ The work done by the force of gravity is 6495.19 Joule

8 0
3 years ago
A solid ball with a mass of 4.25 kg and a
Liono4ka [1.6K]

7.20 units long yea
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