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Dmitry_Shevchenko [17]
3 years ago
8

An upright object 2.80 cm tall is placed 16.0 cm away from the vertex of a concave mirror with a center of curvature of 24.0 cm.

What is the focal length of this mirror?
Physics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

f = 12 cm

Explanation:

<u>Center of Curvature</u>:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of  mirror.

<u>The Radius of Curvature</u>:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of  mirror. It is the distance from pole to the center of curvature.

<u>Focal Length</u>:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

f = \frac{R}{2}

where,

f = focal length = ?

R = Radius of curvature = 24 cm

Therefore,

f = \frac{24\ cm}{2}

<u>f = 12 cm</u>

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Answer:

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b) \Delta S=313.51\ J.K^{-1}

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Given:

  • mass of copper, m_c=2.64\ kg
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  • specific heat capacity of copper, c_c=385\ J.kg^{-1}.K^{-1}
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a)

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)

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Q=m_c.c_c.(T_{ic}-T_{f})

Q=2.64\times 385\times (400-305.7049)

Q=95841.5841\ J

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\Delta S=\frac{dQ}{T}

\Delta S=\frac{95841.5841}{305.7049}

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