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Elis [28]
3 years ago
5

Waves going through a material is called

Physics
1 answer:
Damm [24]3 years ago
7 0
Material medium electric waves
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The least penetrating form of radiation is ____. a. beta radiation c. alpha radiation b. gamma radiation d. X rays
svet-max [94.6K]
C) alpha radiation seems to be the answer

8 0
3 years ago
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A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear
astra-53 [7]

Answer:

a)f_1 = 2070.6 Hz

b)f_2 = 1929.4 Hz

Explanation:

Apparent frequency of the siren is given as

f = \frac{v_{rel}}{\lambda}

as we know that the wavelength will remain the same as it is having originally

sowe know

\lambda = \frac{340}{2000}

\lambda = 0.17 m

a) Now when wind is blowing from source to official

so we have

v_{rel} = 340 + 12 = 352 m/s

so we have

f_1 = \frac{352}{0.17}

f_1 = 2070.6 Hz

b) Now when wind is from official to source

so we have

v_{rel} = 340 - 12 = 328 m/s

so we have

f_2 = \frac{328}{0.17}

f_2 = 1929.4 Hz

4 0
4 years ago
Instantaneous speed is measured
juin [17]
The correct answer is C
4 0
3 years ago
A person is initially driving a car east down a straight road. the magnitude of the instantaneous acceleration is decreasing wit
Alexxandr [17]
By definition, acceleration is the change in velocity per change of time. As time passes by, the time increases in value. So, when the acceleration is decreasing while the time is increasing, then that means that the change of velocity is also decreasing with time. So, optimally, the initial velocity and the velocity at any time are very relatively close to each other,
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3 years ago
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A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northwest. After 25.0s, what is the magnitude
kondaur [170]

Answer:

81.8 m/s

Explanation:

The initial velocity of the plane is:

v_0=115 m/s (toward east)

So, decomposing along the x- and y- directions:

v_{x0} = 115 m/s\\v_{y0} = 0

(we took east as positive x-direction and north as positive y-direction)

The acceleration is

a=2.88 m/s^2 (northwest, so the angle with the positive x-direction is 135 degrees)

Decomposing it along the two directions:

a_x = a cos 135^{\circ} = (2.88 m/s^2)(cos 135^{\circ})=-2.04 m/s^2\\a_y = a sin 135^{\circ} = (2.88 m/s^2)(sin 135^{\circ})=2.04 m/s^2

So the two components of the velocity after a time t = 25.0 s will be

v_x = v_{x0} + a_x t = 115 m/s + (-2.04 m/s^2)(25.0 s)=64 m/s\\v_y = v_{y0} + a_y t = 0 m/s + (2.04 m/s^2)(25.0 s)=51 m/s

So, the magnitude of the velocity of the plane will be

v=\sqrt[v_x^2+v_y^2}=\sqrt{(64 m/s)^2+(51 m/s)^2}=81.8 m/s

6 0
3 years ago
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