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USPshnik [31]
3 years ago
13

Leland hit the target 45 times in 50

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

180

Step-by-step explanation:

200/50=4

45x4=180

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Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ
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Answer:

(-\infty,3)

Step-by-step explanation:

We are given that

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y''+\frac{4}{x-3}y=\frac{x}{x-3}

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By comparing with

y''+p(x)y'+q(x)y=g(x)

We get

p(x)=\frac{4}{x-3}

g(x)=\frac{x}{x-3}

q(x)=0

p(x),q(x) and g(x) are continuous for all real values of x except 3.

Interval on which p(x),q(x) and g(x) are continuous

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By unique existence theorem

Largest interval which contains 0=(-\infty,3)

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Answer:

The given expression will be greater than zero.

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