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Maximizing profit, is a way of getting the highest possible profit, from a function.
The bakery should make 45 loaves of A and 0 loaves of B, to maximize profit
To do this, we make use of the following representations.
x represents source A, and y represents source B
So, we have:
<u>Constraint 1: </u>
A uses 5 pounds, and B uses 2 pounds of oats.
Available: 180
The above condition is represented as;
<u>Constraint 2: </u>
A and B use 3 pounds of flour each.
Available: 135
The above condition is represented as;
<u>Objective function</u>
A yields $40, while B yields $30
So, the objective function is:
So, we have:
Subject to
See attachment for the graph of the subjects
From the graph, we have the corner points to be:
Substitute these values in the objective function
The maximum value of Z is at: (45,0)
This means that: the bakery should make 45 loaves of A and 0 loaves of B, to maximize profit
Read more about maximizing functions at:
