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Yuri [45]
3 years ago
5

-2y + 4 > 10 solve the inequality

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Step-by-step explanation:

-2y+4>10

subtract 4 from both sides

-2y+4-4>10-4

-2y>6

divide both sides by two

-2/2y>6/2

-1y>3

if negative y is greater than three than you have to multiply both sides of the equation by -1

y>-3 if you put that back into the earlier equation it is impossible.

so we have to switch the signs to < or less than

y<-3

Hope that helps:)

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The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

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1 year ago
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