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Illusion [34]
3 years ago
10

in one month darius spends 10 hours walking dogs. How many dogs walks does he do in one month ALSO this is dividing a whole numb

er with a fraction PLEASE ANSWER ASAP!!
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Step-by-step explanation:

let's assume one month is 30 days you would multiply 10 by 30.

10 \times 30 = 300

which would be 300 hours in 1 month

now if one month is 31 days you would simply multiply 10 by 31.

10 \times 31 = 310

which would be 310 hours

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Blizzard [7]

Answer:

(24,13)

Step-by-step explanation:

24 is Sarah's age.

13 is Mike's age.

System:

\left \{24+13=37

I hope this helped!

3 0
3 years ago
What is the approximate distance between the points (1,-2) and (-9,3) on a coordinate grid
jeka57 [31]

<u>Answer</u>

5\sqrt{5} ≈ 11.1803398874989485


<u>Detailed Explanation </u>


We will be using the distance formula for this problem


\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}


Now, let's input the numbers into the formula.


\sqrt{\left(-9-1\right)^2+\left(3-\left(-2\right)\right)^2}


Solve.


Therefore, the distance between the two points is

5\sqrt{5} ≈ 11.1803398874989485

3 0
3 years ago
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mote1985 [20]
We know that (x , y) first we need to find the slop from these two points y2-y1/x2-x1 and your slop will be 25
5 0
3 years ago
The distance from Wakefield to London is 180 miles. A train travels this distance in 2 hours 15 minutes. Calculate the average s
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Answer:

v = 80 mph

Step-by-step explanation:

Given that,

The distance from Wakefield to London is 180 miles.

The train travels this distance in 2 hours 15 minutes.

We need to find the average speed of the train. The average speed of the train is equal to the total distance covered divided by the time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{180\ miles}{(2+\dfrac{15}{60})\ h}\\\\v=80\ mph

So, the required average speed of the train is 80 mph.

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Researching the average earnings by major and by career can help you determine the _____ of an institute of higher education.
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