5 cups & 4 teaspoons
? cups & 6 teaspoons
2.5 cups is half of 5
2 is half of 4
you increased the recipe by 1/2
so for 6 teaspoons you will need 7.5 or 7 1/2 cups of flour b/c 5 + 2.5 = 7.5
ANSWER: 7 1/2
I might not understand this correctly because of the misspellings, but if you draw a right angle. There is only 1 right angle... in a right angle.
Answer:
hello,
Step-by-step explanation:
a)
In an isocele triangle, base's angles have the measure:
42+2a=180
2a=180-42
a=69(°)
b)
in a triangle, an external angle has for measure the sum of the angles not adjacents.
55+b=132
b=77 (°)
c)
in a quadrilater the sum of the (interior) angles is 2*180=360 degrees.
90+90+68+c=360
c=360-90-90-68
c=112 (°)
If the given differential equation is
then multiply both sides by 
:
The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to 
, recalling that 
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)
Solve for 
:
![\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csec%28x%29%20%2B%20C%20%5Ccsc%28x%29%7D%3C%2Fp%3E%3Cp%3Ewhich%20follows%20from%20%5Btex%5D%5Ctan%28x%29%3D%5Cfrac%7B%5Csin%28x%29%7D%7B%5Ccos%28x%29%7D)
.
