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Goryan [66]
3 years ago
15

5 people are trying to sit on a long bench of length 30.52\text{ m}30.52 m30, point, 52, start text, space, m, end text. Find th

e length occupied by each person.
Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

6.104 m

Step-by-step explanation:

The length of the bench is 30.52 m.

5 people want to sit down on the bench.

We assume they are seated with equal spacing between themselves.

The length occupied by each person will therefore be:

30.52 / 5 = 6.104 m

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с. A matched pairs t-interval for a mean difference.

Step-by-step explanation:

With the sample, we will have possession of the sample mean and of the sample standard deviation, which means that the t-distribution will be used.

We want to find the mean number of back problems for each sample, and estimate the difference. Since the groups are similar, with only the positions in which they work being different, we have matched pairs. So the correct answer is given by option c.

7 0
3 years ago
During a sale, a store offered a 15% discount on a TV that originally sold for $420. After the sale, the discounted price of the
wolverine [178]

Answer:

Step-by-step explanation:

Your answer

303.45

Mark it as Brainlist. Follow me for more answer.

7 0
3 years ago
Read 2 more answers
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lana [24]
0.5 of a mile - since 5,280ft = 1 mile and half of 5,280 is 2,640
5 0
3 years ago
I'm calculaing tip and tax on a total cost. Do I need to add th tax to the total, then calculate tip, or calcualte tip on the or
Usimov [2.4K]
You would need to calculate the original cost with the tax then find the tip because the tip is always a percent out of the total cost including tax
4 0
3 years ago
The ubiquitous 12oz aluminum cans used to distribute drinks in this country have a diameter of approximately 2.75 inches and a h
gayaneshka [121]

Answer:

3.5%

Step-by-step explanation:

The volume of a cylinder = \pi r^2h

<em>r</em> = radius of cylinder,

<em>h</em> = height of cylinder

For the non-optimal can,

<em>r</em> = 2.75/2 = 1.375

<em>h</em> = 5.0

V = \pi(1.375^2)\times 5.0 = 9.453125\pi

<em />

For the optimal can,

<em>d</em>/<em>h</em> = 1,

<em>d</em> = <em>h</em>

2<em>r </em>=<em> h</em>

<em>r</em> = h/2

V = \pi\left(\dfrac{h}{2}\right)^2\times h = \pi\left(\dfrac{h^3}{4}\right)

They have the same volume.

<em />\pi\dfrac{h^3}{4} = 9.453125\pi<em />

h^3 = 37.8125

h=3.36 (This is the height of the optimal can)

r = \dfrac{3.36}{2} = 1.68 (This is the radius of the optimal can)

The area of a cylinder is

<em />A = 2\pi r(r+h)<em />

For the non-optimal can,

A = 2\pi\times\dfrac{2.75}{2}\left(\dfrac{2.75}{2}+5.0\right) = 17.53125\pi

For the optimal can,

A = 2\pi\times1.68\left(1.68+3.36\right) = 16.9344\pi

Amount of aluminum saved, as a percentage of the amount used to make the optimal cans = \dfrac{17.53125\pi - 16.9344\pi}{16.9344\pi}\times 100\% = 3.5\%

5 0
3 years ago
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