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2 years ago

8

In the triangle below,

1 answer:

Evgen [1.6K]2 years ago

5 0

Answer:

x=8.6

Step-by-step explanation:

x=8.6

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Can someone help me with question 11

Aleksandr-060686 [28]

Answer:

no i can not

Step-by-step explanation:

6 0

2 years ago

Solve for x. PLEASE SHOW WORK

labwork [276]

Answer:

this is my 50th time seeing you

Step-by-step explanation:

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2 years ago

Find the distance between each pair of points. round your answer to the nearest tenth.

goldenfox [79]

Answer:

5.4

Step-by-step explanation:

To find the distance between each pair of points, we use the distance formula, which is:

d = $\sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2 }$

So we have

$x_{1} = 2\\ x_{2} = 4\\y_{1} = 8\\y_{2}=3$

When we plug in the values into the formula we get:

d = $\sqrt{(4-2)^2 + (3-8)^2}$

d = $\sqrt{4 + 25}\\ =\sqrt{29}\\ =5.4$

3 0

2 years ago

Read 2 more answers

(05.06)A chocolate bar measures 50 mm wide, 90 mm long, and 3 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper

grandymaker [24]

The surface area of a rectangular prism is always:

A=2(xy+xz+yz), where x, y, and z are the three dimensions of the prism.

A=2(50*90+50*3.5+90*3.5)

A=2(4500+175+315)

A=2(4990)

A=9980 mm^2

5 0

3 years ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago