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Ray Of Light [21]
2 years ago
13

Given that f(x) = 3x ^ 3 + x - 1 evaluate the function f(- 2)

Mathematics
1 answer:
Whitepunk [10]2 years ago
4 0

Answer:

-27

Step-by-step explanation:

3(-2)³-2-1 =

3(-8)-3 =

-24-3=-27

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Hey can you please help me posted picture of question
larisa [96]
(5x - 2)^2 = 15

Square root both sides:
5x - 2 = \pm\sqrt{15}

Add 2 to both sides:
5x = pm\sqrt{15} + 2

Divide both sides by 5:
x =  \dfrac{ \pm\sqrt{15} + 2}{5}

Answers:
x = \dfrac{ \sqrt{15} + 2}{5} \ or \ \dfrac{ - \sqrt{15} + 2}{5}

Answer: (B) and (E)

5 0
2 years ago
Read 2 more answers
Solve.and show your work
Marysya12 [62]

Answer:

a) x > − 24 \frac{3}{4}

b) x < − 3

c) q < 56

Step-by-step explanation:

a) −2/5x−9<9/10

<=> 2/5x + 9 > − 9/10

<=> 2/5x > − 9/10 − 9

<=> 2×2/2×5x > − 9/10 − 9×10/10

<=> 4/10x > − 99/10

<=> x > − 99/4

<=> x > − 24 \frac{3}{4}

b) 4x+6<−6

<=> 4x < − 6 − 6

<=> 4x < − 12

<=> x < − 12/4

<=> x < − 3

c) q+12−2(q−22)>0

<=> q+12−2q −2×(−22)>0

<=> (q−2q) + (12+ 44) >0

<=> −q + 56 >0

<=> q < 56

8 0
2 years ago
Solve for <br> 3x + 12= -12
oee [108]

Answer:

x = -8

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides:

3x + 12 (-12) = -12 (-12)

3x = -12 - 12

3x = -24

Next, divide 3 from both sides:

(3x)/3 = (-24)/3

x = -24/3

x = -8

x = -8 is your answer.

~

4 0
3 years ago
Read 2 more answers
20 points and brainlyest to who answers this first in a well format!
djverab [1.8K]

Answer:

in the forth line of the equation it should be this

-6x+10=4x+20

-6x-4x=20-10

-10/-10x=10/-10

x=-1

5 0
2 years ago
What is the solution to the inequality shown? -2(x + 3) &lt; 6 - x x &gt; -12 x &lt; -12 x &gt; 12 x &lt; 12
Sonja [21]

Answer:

x < -12

Step-by-step explanation:

Given the inequality

-2(x + 3) < 6 - x

Expand

-2x - 6 < 6 - x

Collect the like terms;

-2x + x < 6 + 6

-x < 12

Multiply through by -1

-1(-x) < -1(12)

x < -12

6 0
2 years ago
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