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3 years ago

Find the nth term of the sequence0, 5, 14, 27, 44......

Mathematics

1 answer:

Pani-rosa [81]3 years ago

8 0

Answer:

aₙ = 2*n*n - n -1

Step-by-step explanation:

a₁ = 0

a₂ = 5 = 2*2*2 -2-1 = 8-3 = 5

a₃ = 2*3*3 -3-1 = 18-4 =14

a₄ = 2*4*4 - 4-1 = 32-5 =27

......

aₙ = 2*n*n - n -1

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What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle

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Step-by-step explanation:

$\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}$

$\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}$

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$\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}$

$\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2$

$\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}$

$\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}$

$\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}$

$\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4$

$\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}$

$=4.2$

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Find the nth term of the sequence0, 5, 14, 27, 44......​

Find the nth term of the sequence0, 5, 14, 27, 44......