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3 years ago

Factor of 28 that will add or subact to get 3

Mathematics

2 answers:

Crazy boy [7]3 years ago

7 0

4 times 7 gets 28 and 7-4 gets you 3

alexandr402 [8]3 years ago

4 0

They already have the answer above

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HELP PLSSSSSESSSSSSSSSSSS

bekas [8.4K]

Answer:

Step-by-step explanation:

10(3)+2(10)(4)+2(3)(4)=30+80+24

=134

8 0

3 years ago

10=s÷2+7 it really difficult could yall help me out

vladimir2022 [97]

Answer:

The value of s is "90". A further explanation is given below.

Step-by-step explanation:

The given expression is:

⇒ 10=s÷2+7

i.e,

⇒ $10=\frac{s}{2+7}$

On solving the above expression, we get

⇒ $10=\frac{s}{9}$

On applying cross-multiplication, we get

⇒ $10\times 9=s$

⇒ $90 = s$

8 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt2y%2B3%3D11" id="TexFormula1" title="\sqrt2y+3=11" alt="\sqrt2y+3=11" align="absmiddle"

Lady_Fox [76]

Answer:

y = 32

Step-by-step explanation:

sqrt(2y) +3 = 11

Subtract 3 from each side

sqrt(2y) +3-3 = 11-3

sqrt(2y) = 8

Square each side

(sqrt(2y))^2 = 8^2

2y = 64

Divide by 2

2y/2 = 64/2

y = 32

7 0

3 years ago

Read 2 more answers

Answer n.8 for me pls

Nimfa-mama [501]

Answer:

Step-by-step explanation:

(13)2−(2x+7)=0

19x2−2x−7=0

9(19x2−2x−7)=9(0)

x2−18x−63=0

(x−21)(x+3)=0

Therefore, the value of x are

x - 21 = 0 and x + 3 = 0

x = 21 x = -3

5 0

4 years ago