Y - 2 = -3/4 (x - 6)
y = -3/4 (x - 6) + 2
When, x = -2,
y = -3/4 (-2 - 6) + 2 = -3/4 (-8) + 2 = 6 + 2 = 8
One point is (-2, 8)
When, x = 2,
y = -3/4 (2 - 6) + 2 = -3/4 (-4) + 2 = 3 + 2 = 5
Another point is (2, 5)
Answer:
y=(1/2)x+4
Step-by-step explanation:
you have 2 points but in order to find slope intercept you need slope so,
(y2-y1)/(x2-x1)
(-1+4)/(8-2)=1/2 =slope
slope intercept:
y-y1=m(x-x1)
y-2=(1/2)(x+4)
y-2=(1/2)x+2
y=(1/2)x+4
Answer: y = x^2 - 11x + 24
Step-by-step explanation:
Hello!
To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile.
33 - 25 = 8
The interquartile range is 8. Hope I helped! :3
The nth term of the geometric sequence is:
an=ar^(n-1)
where
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
120=ar^2
a=120/(r^2)....i
also:
76.8=ar^(5-1)
76.8=ar^4
a=76.8/r^4.....i
thus from i and ii
120/r^2=76.8/r^4
from above we can have:
120=76.8/r²
120r²=76.8
r²=76.8/120
r²=0.64
r=√0.64
r=0.8
hence:
a=120/(0.64)=187.5
therefore the formula for the series will be:
an=187.5r^0.8
