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vovangra [49]
3 years ago
9

HELP ME 2 PICTURES BTW 50 POINTS

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

7 and 9 are alternate interior angles

Step-by-step explanation:

4 and 11 are corresponding angles

1 and 7 are vertical angles

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NEED HELP WITH THE CORRECT ANSWER AND EXPLANATION!! :p
scoray [572]

Answer: \frac{1}{8}\ lb

Step-by-step explanation:

According to the information given in the exercise, you know that the total amount of butter (in pounds) that were divided evenly, is:

total=\frac{3}{4}\ lb

The exercise explains that they filled six dishes with that division. Therefore, in order to calculate the value of the variable "x", you need to divide \frac{3}{4}\ lb by 6.

But first it is important to remember the Division of fractions:

\frac{a}{b}\div\frac{c}{d}=\frac{a}{b}\div\frac{d}{c}=\frac{ad}{bc}

Therefore, applying that rule, you get:

\frac{3}{4}\ lb\div6=(\frac{3}{4}\ lb)(\frac{1}{6})=\frac{3}{24}\ lb

Finally, reducing the fraction you get the following result expressed as a fraction:

=\frac{1}{8}\ lb

6 0
4 years ago
Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0
3 years ago
Wilmer already has 214 cards. he needs to collect 334 cards. he plans to collect 8 cards each day. find the minimum number of da
Wittaler [7]
The answer is 15 days.

The first step you need to take is to subtract the amount of cards he has from the amount of cards he needs. So 334 (needs) - 214(has) = 120 cards he still needs. So he is collecting 8 cards a day. In order to find out how many days it will take to collect the 120 cards, we need to divide 120 by 8. 120 divided by 8 is 15. So it will take 15 days collecting 8 cards a day in order to reach the 120 cards he still needs to collect.
3 0
3 years ago
What are the greatest common factors of 48a^6 and 38a?
professor190 [17]
The greatest common factor is 2a
5 0
3 years ago
Read 2 more answers
Solve the following system of equations using the elimination method. 4x + 2y = 12 4x + 8y = –24
Hunter-Best [27]

Answer:

my answer for y is -6, x is -10

Step-by-step explanation:

just eliminate the -4s by subtracting them and you will get the value of y.

now you can use either eqn (I) or (ii) which are first and second.

anyone you decide to choose just replace y by the value you got and you will get the value of x.

pls try to do it buddy you can

4 0
2 years ago
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