Depreciation is the decrease in value of a given asset within a given period of time.
Using the formula, A=P(1-r/100)^n, where A is the new value after depreciation, P is the original value, r is the depreciation rate and n is the time taken.
Therefore,
A = 24500(0.8525)^14
= 2623.54 dollars
≈ 2623.50 dollars
Thus the value after 14 years will be 2623.50 dollars
Suppose she paid x shillings for the shares;
Then;
37+9=2x
46=2x
x=23
She bought each share at 23 dollars
RemarkThe very first thing you should do with a question like this is get the graph. Then you will know what you are looking for. I have provided you with such a graph. Your table should center around -2 ≤ x ≤ -1
So let's set up a table and see what we get. Start with y = x + 5
x x + 5
-1 4
-1.25 3.75
-1.5 3.5
-1.75 3.25
-2 3
Do the same thing for - (3)^x + 4 See below to see how this is entered your calculator
x -(3)^x + 4
-1 3.66
-1.25 3.75
-1.5 3.8
-1.75 3.85
-2 3.89
ConclusionWhen x = - 1.25 y = 3.75 for both graphs. <<<< Answer
FootnoteYou may not be familiar with how to put this in your calculator. This is the way I would do it. I'm only doing it for y = -(3^x) + 4
Let x = - 1.25
3
^ Note your calculator might have x^y or y^x. You'll have 1 of the three.
1.25
+/-
=
X
1
+/-
= At this point you should have -0.25
+
4
=
That gives you 3.75
Answer:
1/3(n) - 3 < 6; n < 27
Step-by-step explanation:
" 3 subtracted from one third of a number"
= 1/3(n) - 3
given that this is less than 6:
1/3(n) - 3 < 6
1/3(n) < 6 +3
1/3(n) < 9
n < 27
You need to select any numbers that are greater than 28.
If you entered the number 27 in the missing space, you would have two numbers that are equal to each other. However, we want the right side to be larger so we need to select anything larger than 27.