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3 years ago

Find the value of x in the parallelogram.

Mathematics

2 answers:

levacccp [35]3 years ago

8 0

The answer is x=4

Hope this helps

olga_2 [115]3 years ago

7 0

the answer to this question is

x=4

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Use Fermat's Little Theorem to determine 7^542 mod 13.

m_a_m_a [10]

$a^{p-1} \equiv 1 \pmod p$ where $p$ is prime, $a\in\mathbb{Z}$ and $a$ is not divisible by $p$ .

$7^{13-1}\equiv 1 \pmod {13}\\7^{12}\equiv 1 \pmod {13}\\\\542=45\cdot12+2\\\\7^{45\cdot 12}\equiv 1 \pmod {13}\\7^{45\cdot 12+2}\equiv 7^2 \pmod {13}\\7^{542}\equiv 49 \pmod{13}$

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3 years ago

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If x = 3 and y = -2, what is the value of the expression x^3-2xy^2?

Nana76 [90]

Answer:

Step-by-step explanation:

The expression is $x^3-2xy^2$ . To find the value, substitute the values x = 3 and y =-2 then follow order of operations.

$x^3-2xy^2\\3^3 -2(3)(-2)^2\\27 -2(3)(4)\\27 - 24\\3$

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3 years ago

How to memorise times tables

kaheart [24]

Its very hard to memorise them but if you practice and keep practicing you might get the hang of them. But heres a little trick alright? For the 11ths tables every except 12 will be 11,22,33 etc.. for instance 5 times 11 equals 55 or 8 times 11 equals 88.

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3 years ago

Find the GCF of 16 and 27.

xeze [42]

The greatest common factor is 1

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3 years ago

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Use the quadratic formula to si<br> 3x2 + 8x – 4= 0

omeli [17]

Answer:

$\large\boxed{x=\dfrac{-4-2\sqrt7}{3}\ or\ x=\dfrac{-4+2\sqrt7}{3}}$

Step-by-step explanation:

$\text{The quadratic formula for a quadratic equation}\ ax^2+bx+c=0\\\\\text{determinant:}\ \Delta=b^2-4ac\\\\\text{If}\ \Delta0,\ \text{then the equation has two different solutions}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}.$

$\text{We have:}\\\\3x^2+8x-4=0\\\\a=3,\ b=8,\ c=-4\\\\\Delta=8^2-4(3)(-4)=64+48=112>0\\\sqrt\Delta=\sqrt{112}=\sqrt{(16)(7)}=\sqrt{16}\cdot\sqrt7=4\sqrt7\\\\x=\dfrac{-8\pm4\sqrt7}{2(3)}=\dfrac{-8\pm4\sqrt7}{6}=\dfrac{2(-4\pm2\sqrt7)}{6}=\dfrac{-4\pm2\sqrt7}{3}$

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3 years ago