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3 years ago

Find the value of x in the parallelogram.

Mathematics

2 answers:

levacccp [35]3 years ago

8 0

The answer is x=4

Hope this helps

olga_2 [115]3 years ago

7 0

the answer to this question is

x=4

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A company logo is shaped like an equilateral triangle with 2-in.-long sides. What is the height of the logo? Round to the neares

deff fn [24]

Answer:

B. 1.7 in

Step-by-step explanation:

Divide the triangle into 2 congruent right angle triangles

With hypotenuse: 2

Base: 2/2 = 1

Using pythagoras theorem

2² = 1² + h²

h² = 3

h = sqrt(3)

h = 1.732050808

6 0

3 years ago

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-4.8[6.3x-4.8]=-58.56

DENIUS [597]

Answer:

=2.6984126984

Step-by-step explanation:

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2 years ago

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Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

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2 years ago

What is (f-g)(x)?<br><br> question equation show in picture

likoan [24]

Answer:

(f-g)(x) = x^4 - x^3 - 4x^2 - 3

Step-by-step explanation:

(f-g)(x) = x^4 - x^2 + 9 - (x^3 + 3x^2 + 12)

(f-g)(x) = x^4 - x^2 + 9 - x^3 - 3x^2 - 12

(f-g)(x) = x^4 - x^3 - 4x^2 - 3

7 0

3 years ago

During the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours.The second one was

butalik [34]

Answer:

2nd debate was 3 hours long.

Step-by-step explanation:

We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.

Let us find the estimate of time spent on 2nd debate.

1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.

$2*2=4$