24cm.........................................
In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call
![x](https://tex.z-dn.net/?f=x)
) and the length of the hypotenuse. This sets you up with the relation
![\sin2^\circ=\dfrac x{1600}\implies x\approx55.84\text{ m}](https://tex.z-dn.net/?f=%5Csin2%5E%5Ccirc%3D%5Cdfrac%20x%7B1600%7D%5Cimplies%20x%5Capprox55.84%5Ctext%7B%20m%7D)
In 23, you're given a similar situation, except now you're looking for the angle (I'll call it
![\theta](https://tex.z-dn.net/?f=%5Ctheta)
) in the triangle opposite the side denoting the height of the airplane. So this time,
Answer:
i think it's a
Step-by-step explanation: