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belka [17]
3 years ago
14

20 points five stars a thank you, dont need to awnser first. i will repeat this question every 3 and a half minutes. ive got nin

e hundred points to burn
Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

Thank you

Step-by-step explanation:

PolarNik [594]3 years ago
6 0

Answer:

Thank you

Step-by-step explanation:

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A triangle has sides with lengths of 5 meters, 12 meters, and 13 meters. Is it a right triangle?
Setler [38]

Answer:

yes :

use the following formula :

a^2 +b^2 = c^2

now apply it to the problem :

5^2+12^2=13^2

do the exponent :

25 + 144 =169  

now add

169 =169

if they are equal , then it is a right triangle .

7 0
3 years ago
Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal
Elina [12.6K]

Answer:

The correct answer would be 2:1

Step-by-step explanation:

In order to find this, start with the ratio as it is written and sub in the values. Then simplify to the lowest possible terms.

Ran:Walker

8:4

2:1

6 0
3 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Solve<br> 6(x-3) + 10 = 2(4x-5)
Firdavs [7]
6x-8=8x-10 then 2=2x which means x=1
6 0
3 years ago
Read 2 more answers
marty has 1 1/3 jugs of apple juice. he uses 3/4 of the juice to make freeze pops. what fraction amount of a jus doe marty have?
Vedmedyk [2.9K]

Answer:

=2\frac{1}{12}  

Step-by-step explanation:

We have to make the fractions equal so we can add them

1 \frac{1}{3}×4= 1\frac{4}{12}

\frac{3}{4}×3=\frac{9}{12}

1\frac{4}{12}+\frac{9}{12}=2\frac{1}{12}  

5 0
3 years ago
Read 2 more answers
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