What is the equation of a line that passes through the points (3, 6) and (8, 4)?
1 answer:
9514 1404 393
Answer:
y = -2/5x +36/5 . . . . . slope-intercept form
2x +5y = 36 . . . . . . . . standard form
Step-by-step explanation:
You can use the 2-point form of the equation of a line to find it.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (4 -6)/(8 -3)(x -3) +6
y = -2/5(x -3) +6
y = -2/5x +36/5 . . . . slope-intercept form
2x +5y = 36 . . . . . . . standard form
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B
given f(x) in factored form, equate to zero for x-intercepts
(x - 8)(x - 4) = 0, hence
x = 4, x = 8 ← x- intercepts
The vertex lies on the axis of symmetry which is situated at the midpoint of the x- intercepts
x- coordinate of vertex = = 6
f(6) = (6 - 8 )(6 - 4 ) = -2 × 2 = - 4 ← y-coordinate
vertex = (6, - 4 ) → B