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Answer:
Explained below.
Step-by-step explanation:
The human resource department at a certain company wants to conduct a survey regarding worker morale. The department has an alphabetical list of all 4,502 employees at the company and wants to conduct a systematic sample of size 50.
Systematic sampling is a kind of probability sampling method in which individuals from a larger population are nominated according to a random initial point and a static, periodic interval.
(a)
A sample of size 50.
Then the value of <em>k</em> will be: 
Thus, the value of <em>k</em> is 90.
(b)
Label the employees from 1 to 4502.
And select every 90th employee.
So, the individuals who will be administered the survey are:
90th, 180th, 270th,...
Answer:
5/9
Step-by-step explanation:
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
If my simplification is valid the answer is:
1.4 % growth each minute
I don’t feel like the representation
P = 120(1.82) is important in this certain problem.
So P the predicted number of bacteria is not practical with this problem.
Use the 82% per hour and divide it by 60 because there are 60 minutes in an hour.
When doing this you find the rate in which bacteria grows which is about 1.4%.
The prediction is about 1.82 percent for 120 something it’s not clarified, but I’m guessing that’s minutes.
So you can prove that the prediction is over the rate in which bacteria grows per minute.
