A sack full of medals contains gold, silver, and bronze. If selected at random, the probability of picking a gold medal is 5/12.
The probability of picking a silver medal is 1/3. What is the probability of picking a bronze medal
1 answer:
Answer:

Step-by-step explanation:
Given


Required
Determine the probability of Bronze medal
In probability, sum is always equal to 1
i.e.

Make Bronze the subject

Substitute values for Gold and Silver

Take LCM



Hence:
The probability of picking bronze is

You might be interested in
C = 2 (pi) r
32 (pi) = c
32 (pi)= 2 (pi) r
r= 16
2r = d
d= 32
hope that helps
I think it would be 4.5:5
:/ hope this might of helped
lol might have done it wrong tho
Here, both numbers are divisible by 7 so that brings you to 9:4
Answer:
Step-by-step explanation:
The "product of 4 and 5" is (4)(5). 12
The quotient of 12 and the product of 4 and 5 is ------------
(4)(5)
Answer:

Step-by-step explanation:
![( \frac{625}{16} {)}^{ \frac{1}{4} } \\ \sqrt[4]{ \frac{625}{16} } = \frac{ \sqrt[4]{625} }{ \sqrt[4]{16} } \\ \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{16} } = \frac{ \sqrt[4]{ {5}^{4} } }{ \sqrt[4]{ {2}^{4} } } = \frac{5}{2}](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B625%7D%7B16%7D%20%20%7B%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%5C%5C%20%20%5Csqrt%5B4%5D%7B%20%5Cfrac%7B625%7D%7B16%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B625%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B16%7D%20%7D%20%20%20%5C%5C%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B%20%7B5%7D%5E%7B4%7D%20%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B16%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B%20%7B5%7D%5E%7B4%7D%20%7D%20%7D%7B%20%5Csqrt%5B4%5D%7B%20%7B2%7D%5E%7B4%7D%20%7D%20%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7B2%7D%20)
