1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alecsey [184]
2 years ago
10

A store manager wants to determine how much to pay her employees. The number of hours the employees work is x, and the hourly wa

ge that they are paid is y. The store manager is willing to pay the employees a wage given by the equation 10y-30x=20 . The business owner states that the employees should be paid a wage given by the equation 6y+30x=60. If the two equations were added then simplified to determine hourly wage, y, how much would the employees be paid?
Mathematics
1 answer:
Ivanshal [37]2 years ago
6 0

Answer:

<em>The employees will work for 1 hour, will earn $5 per hour and will be paid $5</em>

Step-by-step explanation:

<u>System of Equations</u>

The number of hours the employees work is x.

And the hourly wage that they are paid is y. The store manager is willing to pay the employees a wage given by the equation

10y-30x=20

The business owner states that the employees should be paid a wage given by the equation

6y+30x=60

Adding both equations we have:

16y = 80

Dividing by 16:

y = 80/16 = 5

Substituting into the first equation:

10*5-30x=20

Operating and simplifying:

50-30x=20

50 - 20 = 30x

30x = 30

x = 30/30 = 1

Thus, the employees will work for 1 hour, will earn $5 per hour and will be paid $5

You might be interested in
Maria makes beaded necklaces. She charges a rate of $0.75 per inch in length plus $0.25 per bead as shown in the expression, whe
sergiy2304 [10]
16x+60y
16(.75)+60(.25)
12+15=27
maria would charge $27 for this necklace
3 0
3 years ago
Read 2 more answers
Activity where are you going​
Vaselesa [24]

Answer:

I will center school one year from now despite the fact that my acumen is far more noteworthy than the normal sixth grader

3 0
3 years ago
Hi! Answer this please!
Rudiy27
The answer would be b
4 0
2 years ago
Read 2 more answers
I need help with this one exercise to finish so any help would be greatly appreciated!
Elodia [21]

Answer:

No Solutions

Step-by-step explanation:

for |4x -3| + 10 < 2

|4x - 3| < -8

Not possible since absolute value is positive

4 0
2 years ago
The height
andre [41]

The ball describes a parabola, as you can see in the attached picture. So, the point where the ball strike the ground is the point where the parabola meets the x axis. In fact, the x-axis is the set of points where y=0, which means that the ball has height 0 or -again- it hits the ground.

So, we have to set y=0 in our equation and look for the positive solution. We have

-\dfrac{1}{14}x^2+6x+3=0 \iff x=42\pm\sqrt{1806}

And the positive solution is

42+\sqrt{1806}

So that's the distance from the child where the ball strikes the ground.

6 0
3 years ago
Other questions:
  • One astronomical unit is about 93,000,000 miles. At 20,000 miles per hour how many astronomical units can Orion travel? ( Orion
    15·1 answer
  • Fill the solution to the following equations​
    12·1 answer
  • Do many fishermen collect worms at night?
    13·1 answer
  • PLEASE HELP?
    8·1 answer
  • A bag contains yellow marbles and blue marbles, 23 in total. The number of yellow marbles is 7 less than 2 times the number of b
    11·1 answer
  • Evaluate the expression using the Commutative and Associative properties of numbers.
    11·1 answer
  • How many groups of 3/4 are in each of the following quantities? 6 1/2<br> answer as a fraction
    7·1 answer
  • A, B and C are collinear points. B is between A and C. AB=12 BC=18 AC=3x Find X.
    11·1 answer
  • Just do b d f h and j​
    14·1 answer
  • Milena is trying to determine an algebraic expression to represent the amount of punch she needs to make for her party. She does
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!