Answer:
a. Chi-square test of independence
Step-by-step explanation:
The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.
In the given problem the Equal , more or less are the attributes.
The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
If the balance is growing exponentially the balance after 45.4 months will be $44,925.94.
Step-by-step explanation:
The exponential growth equation is:

Compute the value of f (x) for <em>x</em> = 45.4 as follows:


Thus, if the balance is growing exponentially the balance after 45.4 months will be $44,925.94.
Step-by-step explanation:
Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).
As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):
1) 512 => 2 partecipants
2) 256 => 4 partecipants
3) 128 => 8 partecipants
4) 64 => 16 partecipants
5) 32 => 32 partecipants
6) 16 => 64 partecipants
7) 8 => 128 partecipants
9) 4 => 256 partecipants
10) 2 => 512 partecipants
The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.
Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.
Rational number is the term that describes 15/18