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Kryger [21]
2 years ago
5

The following set of random numbers represents 20 simulations of three daily

Mathematics
1 answer:
babunello [35]2 years ago
3 0

The number of simulations in which was there was an on-time departure for all three flights is; 6

<h3>How to carry out number simulations?</h3>

We are given;

Number of Simulations = 20

Numbers that represent late departure = 0, 1, 2 or 3

Numbers that represent On-time departure = 4, 5, 6, 7, 8 or 9.

Now, the 20 simulations as seen online are;

339 931 317 444 432 858 194 192 649 709

742 626 702 258 955 880 505 854 774 132

To know the number of simulations that were on-time departure, we need to find the ones that don't include 0, 1, 2 or 3.

Looking at the simulations, the ones that represent on-time departure are 444, 858, 649, 955, 854, 774.

Thus, there are 6 simulations in which was there an on-time departure for all three flights

Read more about Number Simulations at; brainly.com/question/1459420

#SPJ1

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Sunny_sXe [5.5K]
So thi sis really simple since you have an equal sign so



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to subtract fractions, make the bottom number the same
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tada
n=-2/3
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3 years ago
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9/20+3/18 i need help witth this question
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2. Solve the<br> triangle.<br> a = 12, b = 22, C = 95°
djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4

Step-by-step explanation:

7 0
2 years ago
Find the LCM and GCF of 8<br>and 12<br>LCM<br>GCF​
Vesnalui [34]

Answer:

LCM: 24

GCF: 4

Step-by-step explanation:

LCM: guess and check by multiplying the largest number by an integer and dividing the product by the smaller number to check. 12*2=24 ... 24/8=3 ✓

GCF: opposite the other: guess and check by dividing the smaller number by an integer and multiplying the quotient by the larger number to check.

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