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3 years ago

Sooooooooo, I need Help PLEASE!!!!!!

Mathematics

1 answer:

dem82 [27]3 years ago

6 0

Answer: Sorry, can you repost and comment on this post to reach out to me with a clear pic bc the light is blocking the center of the page

Step-by-step explanation:

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F(x)=2x^2-x+1 find the vertex

Galina-37 [17]

The Answer fam is (1/4,7/8)

5 0

3 years ago

Whats the answer for this

drek231 [11]

Answer:

50/18 or 2.77

Step-by-step explanation:

So first u have to make the 3 1/3 and 1 1/5 into improper fractions.

Then, you can do the keep, change, flip thing and then u get 10/3 x 5/6 to get 50/18

7 0

3 years ago

Read 2 more answers

Please help like now

garik1379 [7]

Answer:

12f + 49g

Step-by-step explanation:

12f -7g(-7)

12f + 49g

7 0

3 years ago

A new car worth $20,000 loses 20% of its value every year. Is the value of the car represented by a linear or exponential functi

madreJ [45]

Exponential.

One way to think about this, is to ask how much you will lose each year. The first year you're losing 20% of $20,000 ($4,000). The second year you're losing 20% of 16,000 ($3,200). The dollar value your car loses each year diminishes exponentially, so it is not a linear but an exponential function.

7 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: