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Airida [17]
3 years ago
12

Stion Factor the difference of squares. x2 - 400 The factored form of x2 - 400 is

Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

The factored form of x²-400 is (x+20)(x-20).

Step-by-step explanation:

Given the expression

x^2\:-\:400

As the square of 20 is 400. Therefore, rewrite 400 as 20²

⇒ x^2-20^2

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

Thus, the expression becomes

x^2-20^2=\left(x+20\right)\left(x-20\right)

Thus, the factored form of x²-400 is (x+20)(x-20).

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xxTIMURxx [149]
(4x+1)(x+6). 
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3 years ago
A baker buys 19 apples of two different varieties to make pies. The total cost of the apples is $5.10. Granny Smith apples cost
Natasha2012 [34]

The baker bought 7 gala apples, and 12 granny smiths apples

<em><u>Solution:</u></em>

Let "x" be the number of gala apples bought

Let "y" be the number of granny smith apples bought

Cost of 1 gala apple = $ 0.30

Cost of 1 granny smith apple = $ 0.25

<em><u>A baker buys 19 apples of two different varieties to make pies</u></em>

Therefore,

number of gala apples bought + number of granny smith apples bought = 19

x + y = 19 --------- eqn 1

<em><u>The total cost of the apples is $5.10</u></em>

Therefore, we can frame a equation as:

number of gala apples bought x Cost of 1 gala apple + number of granny smith apples bought x Cost of 1 granny smith apple = 5.10

x \times 0.30 + y \times 0.25 = 5.10

0.3x + 0.25y = 5.1 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 19 - y ---------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.3(19 - y) + 0.25y = 5.1

5.7 - 0.3y + 0.25y = 5.1

5.7 - 0.05y = 5.1

0.05y = 5.7 - 5.1

0.05y = 0.6

y = 12

<em><u>Substitute y = 12 in eqn 3</u></em>

x = 19 - 12

x = 7

Thus the baker bought 7 gala apples, and 12 granny smiths apples

6 0
3 years ago
4x−4&lt;8 AND 9x+5&gt;23 Solve for X.
siniylev [52]

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5 0
2 years ago
2) Evaluate the given numerical expression.<br><br> A) 9<br> B) 12<br> C) 14<br> D) 21
eduard

Answer:

  • \boxed{\sf{14}}

Step-by-step explanation:

\boxed{\underline{\text{ORDER OF OPERATIONS:}}}

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

<u>PEMDAS</u>

  • <u>Parentheses</u>
  • <u>Exponents</u>
  • <u>Multiply</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>BODMAS</u>

  • <u>Brackets</u>
  • <u>Order</u>
  • <u>Divide</u>
  • <u>Add</u>
  • <u>Subtract</u>

<u>First, do parentheses.</u>

3+6*(5+4)÷3-7

(5+4)=9

\Longrightarrow: \sf{3+6* 9\div 3-7}

<u>Do multiply and divide.</u>

6*9=54

54/3=18

<u>Then, rewrite the problem down.</u>

\Longrightarrow: \sf{3+18-7}

<u>Add.</u>

\sf{3+18=21}

\sf{21-7=\boxed{\sf{14}}

\Longrightarrow: \boxed{\sf{14}}

  • <u>Therefore, the correct answer is "C. 14".</u>

I hope this helps, let me know if you have any questions.

8 0
2 years ago
Homework
jenyasd209 [6]

Answer:

6,9 hope this is it

Step-by-step explanation:

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