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3 years ago

I need some help please

Mathematics

1 answer:

Ket [755]3 years ago

8 0

Answer:

3 $\sqrt{5}$

Step-by-step explanation:

View the distance as a hypotenuse of a triangle ΔABC (∠C = 90°).

Use Pythagorean theorem:

AB = y1 - y2 = 9 - 6 = 3

AC = x1 - x2 = 4 - (-2) = 6

Now calculate BC which is also the distance needed:

$BC^{2} =AC^{2} +AB^{2}$

$BC^{2}$ = $6^{2} + 3^{2}$ = 45

BC = $\sqrt{45}$ = $\sqrt{3 * 3 * 5}$ (BC > 0)

BC = 3 $\sqrt{5}$

Make me the brainliest ;)

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4 years ago

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