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Aleks04 [339]
3 years ago
15

What is the difference between ordering numbers, comparing numbers, and comparing amounts?

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

different definitions

Step-by-step explanation:

ordering numbers can be seen as arranging the numbers by a certain characteristics. for example, you could order numbers from least to greatest

comparing numbers can be seen as looking into two or more numbers rather than the entire group of numbers. for example, if there were the numbers 1, 2, 3, 4, 5, 6, you could say that 2, 4, 6, are even numbers

comparing amounts could be determined by worth but not the numerical values. for example, you could have a gallon of milk and a quart of orange juice but just by the size of the container, a gallon of milk is bigger and holds more than a quart of orange juice

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3 years ago
A tank holds 50 gal of water, which drains from a leak at the bottom, causing the tank to empty in 20 min. The tank drains faste
kirza4 [7]

Answer:

(a) V(0) = 50 gal, V(20) = 0 gal

(b)At t= 0 the tank is full.

At t=0 the tank is empty

(c)

Time       volume

 0               50 gal

 5                37.5 gal

 10              25 gal

 15             12.5 gal

20                0 gal

(d)

Net change of volume = 50 gal

Step-by-step explanation:

Given that the capacity of the tank is 50 gal.

Torricelli's Law gives the volume of water remaining in the tank after t minutes as

V(t)=50(1-\frac{t}{20})^2

(a)

To find V(0), we put t = 0 in the above equation

V(0)=50(1-\frac{0}{20})^2

        =50(1-0)^2

        = 50 gal

To find V(20), we put t =2 0 in the above equation

V(20)=50(1-\frac{20}{20})^2

        =50(1-1)^2

        = 0 gal

(b)

At t= 0 the tank is full.

At t=0 the tank is empty.

(c)

Time                                          V(t)

  0                                  50(1-\frac{0}{20})^2=50 \ gal

  5                                  50(1-\frac{5}{20})^2=37.5 \ gal

 10                                  50(1-\frac{10}{20})^2=25 \ gal

 15                                 50(1-\frac{15}{20})^2=12.5 \ gal

 20                                50(1-\frac{20}{20})^2=0

(d)

Net change of volume = V(0) -V(20)

                                     =(50-0) gal

                                    = 50 gal

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