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2 years ago

PLEASE HELP HOW DO I DO THIS

Mathematics

1 answer:

KIM [24]2 years ago

5 0

Answer:

90.025

Step-by-step explanation:

i dont know if this is correct but i divided 361 by 4 and that was my answer

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mr.wilson saved 2,500 to buy airlines tickets he bought airline tickets for $372 each how much savings does mr.wilson after he b

ozzi

2,500 subtracted by 372 equals 2148. 2148 dollars is how much savings he has left.

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3 years ago

Read 2 more answers

Annalee hammered in nail into a piece of wood each time she hammer the nail it went to 1/8 Inch deeper into the word if she hamm

mash [69]

Answer: 0.5 inch

Step-by-step explanation:

Given

On hammering nail advances $\frac{1}{8}\ inch$ each time

Annalee hammered 4 times

So, total advancement of nail= $4\times \dfrac{1}{8}=\dfrac{1}{2}\ inch$

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2 years ago

Simi bought a study table for $ 9000. She sold it at a profit of 20%. How much profit did she make? What is the selling price?

pashok25 [27]

Answer:

cost price of a table=$9000

profit%=20%

Let profit be x

to find profit use formula,

profit%=profit/cost price*100

20%=x/$9000*100

20*$9000=100x

$180000/100=x

$1800=x

Now to find selling prie os a table use formula,

cost price +profit

$9000+$1800

$91800

therefore selling price of a table is $91800

Step-by-step explanation:

Hope this helps u!!

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2 years ago

Together, kamela and Leo have 198 stamps. Kamela’s collection has 62 more stamps Thant Leon’s collection. How many stamps does L

Rufina [12.5K]

Leo has 99 stamps compared to kamela

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2 years ago

A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200

kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$ = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

( 10 ±4 )

( 10 -4 , 10+4)

( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0

2 years ago