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bixtya [17]
3 years ago
6

What is the solution for d=rt for t

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

t= \frac{d}{r}

Step-by-step explanation:

comon sence

Hope this help you

<3

Red

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\frac{(x+5)(x-5)}{(x-5)(x+2)}
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What is 20 time 4 equal?
IRISSAK [1]
20 multiplied (times) 4 is equal to 80 c:
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4 years ago
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Li bought his dog Spot a huge bone. Spot chews 4 inches off the bone every day. What number describes the change in the length o
Anarel [89]

Answer:

4 x 3 = 12

12 is the answer. Have a great day

Step-by-step explanation: Brainliest please

4 0
3 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that \mu = 5.8, \sigma = 0.8

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

Z = \frac{X - \mu}{\sigma}

-1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = -1.74*0.8

X = 4.41

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

Z = \frac{X - \mu}{\sigma}

1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = 1.74*0.8

X = 7.19

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0
3 years ago
Sam rolls a fair dice and flips a fair coin.
wolverine [178]

Answer:

The probability that this occurs is 25%, as 3/6 (chance to roll an odd number) multiplied by 1/2 (chance to flip a head) is .25.

Step-by-step explanation:

8 0
3 years ago
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