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NNADVOKAT [17]
2 years ago
11

Sinead buys a watch

Mathematics
1 answer:
taurus [48]2 years ago
5 0

Answer:

£50 is the answer

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If sine ⁡theta equals negative 8/17 and the terminal side of theta lies in quadrant IV, find cosine ⁡ theta .
Lelechka [254]
\sin^2\theta+\cos^2\theta=1\implies \cos\theta=\pm\sqrt{1-\sin^2\theta}

Since \sin\theta=-\dfrac8{17}, it follows that

\cos\theta=\pm\sqrt{1-\dfrac{64}{289}}=\pm\sqrt{\dfrac{225}{289}}=\pm\dfrac{15}{17}

where the sign depends on the location of the terminal side of the angle. Since the terminal side lies in the fourth quadrant, that means the cosine of the angle is positive, so

\cos\theta=\dfrac{15}{17}
3 0
3 years ago
Write inequalities to describe the solid left (x < 0 is left) hemisphere of a sphere of radius 4 centered at the origin
Serggg [28]
The equation of the sphere centered at 0, and radius 4 is:

\displaystyle{ x^2+y^2+z^2=4^2, 

note that this equation describes exactly the points of the surface of the square. That is, this is an EMPTY sphere.

The solid sphere, that is the points on the surface and all points in the inside, are given by :

\displaystyle{ x^2+y^2+z^2 \leq 4^2


since we want the left part of the solid part, picture 2, we add the condition x<0,


thus "the solid left (x < 0 is left) hemisphere of a sphere of radius 4 centered at the origin" is given by the system of inequalities:

i) \displaystyle{ x^2+y^2+z^2 \leq 4^2
ii)x\ \textless \ 0

8 0
3 years ago
Read 2 more answers
A researcher says to the respondents in a poll, “Eating too many sugary foods leads to cavities. Would you rather have soda or w
seropon [69]

Answer:

huh

Step-by-step explanation:

3 0
3 years ago
The problem has been started for you. 8 StartLongDivisionSymbol 468 EndLongDivisionSymbol minus 40 = 68. 68 minus 64 to get a re
stich3 [128]

Answer:

58

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
SBC is an isosceles triangle with main vertex S.
stira [4]

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

4 0
1 year ago
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