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3 years ago

I NEED HELP PLEASEE ASAP

Mathematics

1 answer:

tiny-mole [99]3 years ago

5 0

Answer:

-5 and initial value is -1

Step-by-step explanation:

Slope= y2-y1/x-x1

-11-(-1)/2-0

-10/2

-5

Initial value is y-intercept where x is 0 (0,y)

(0,-1) is starting point

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What is 2 to the power of 4/3 equal to

Reika [66]

Answer:

<h2><u>E</u><u>k</u>sponent</h2>

$\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m} } = \sqrt[m]{ {a}^{n} } } } }}$

$\sf{ {2}^{ \frac{4}{3} } }$

$= \sqrt[3]{ {2}^{4} }$

$= \sqrt[3]{2 \times 2 \times 2 \times 2}$

$= \boxed {\bold{\sqrt[3]{16}(c.) }}$

4 0

2 years ago

Help me with this question

stealth61 [152]

C the bank will exchange his new car for a old one

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4 years ago

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On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

4 years ago

I need help with both of these

jeka57 [31]

Answer:

13x² - 19x + 23
-16x +17

Step-by-step explanation:

1 . (4x² - 9x + 16) + (7 + 9x² - 10x)

4x² - 9x + 16 + 7 + 9x² - 10x

13x² - 19x + 23

2 . (-2x + 6) - (14x - 11)

-2x + 6 - 14x + 11

-16x +17

8 0

3 years ago

Work out the size of the angle X.<br><br> Give your answer correct to 3 significant figures.

aleksley [76]

Step-by-step explanation:

Recall the Ratio for tan

Tan(theta) = opposite / adjacent

Tan (x) = 9 / 5

solve for x (use Tan^-1(...) )

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3 years ago

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