NEED ANSWER ASAP!!!! y=−x^2−2x+3 When is g(x) = 0?
1 answer:
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Answer:
<em>The required points of the given line segment are ( - 1, - 5 ).</em>
Step-by-step explanation:
Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -
As we know that-
If a line segment AB is with endpoints ( ) and (
)then the mid points M are-
<em>M = ( ,
)</em>
Here,
<em>Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -</em>
then by the midpoint formula M are-
<em>( 3, - 2 ) = ( ,
)</em>
On comparing x coordinate and y coordinate -
We get,
<em>( = 3 ,
= - 2)</em>
<em>( 7 + x = 6, - 9 + y = - 4 )</em>
<em>( x = 6 - 7, y = - 4 + 9 )</em>
<em>( x = - 1, y = -5 )</em>
<em>Hence the required points A are ( - 1, - 5 ).</em>
<em>We can also verify by putting these points into Midpoint formula.</em>
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The general equation of line with the slope "m" and passing points (a,b) is :
y - b = m (x -a)
In the given question:
Slope m = -2, passing points (a,b) = (4,-4)
Substitute the value of a = 4, b = -4 in the general equation of line
The equation with the slope -2 and passing points (4,-4) is 2x + y = 4
Answer : 2x + y = 4