h(x) = 3x + 5
h(a) = 27
We can write this as 3a + 5 = 27
Now, we just need to solve for a.
<em><u>Subtract 5 from both sides</u></em>
3a = 22
<em><u>Divide 3 from both sides.</u></em>
a = 7.33
Now, let's plug 7.33 back into the original equation.
3 * 7.33 + 5 = 27
22 + 5 = 27
27 = 27 √ this is correct
Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
one answer
Step-by-step explanation:
set the equal to each other and you get one answer
2x+6= -3x -4
Answer:
÷ -2
Step-by-step explanation:
