I’m confused on this one

Mathematics

1 answer:

UkoKoshka [18]3 years ago

8 0

The ratios in a 30-60-90 triangle are 1 : $\sqrt[2]{3}$ : 2. Therefore, since the hypotenuse is the longest and it is 10, 10 / 2 is 5 meaning 5 is the smallest side.

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Make a conjecture about the next item in the sequence 1, -4, 9, -16

Snezhnost [94]

To get -4 from 1, we must either subtract 5 from 1 or mult. 1 by -4. Unfortunately subtracting 5 from -4 does not result in 9, and mult -4 by -4 does not result in -16. So neither "works" in predicting the next term.

Can you think of any other experiments to do that would help you discover the pattern 1, -4, 9, -16?

4 0

3 years ago

Read 2 more answers

PTG has side lengths of 18 cm, 27 cm, and 13 cm. which type of triangle is PTG? The answer is obtuse.

Verizon [17]

To know what kind of triangle is it. use the pythagorean theorem:
A^2 + B^2 = C^2,
where C is the longest side of the triangle
if it satisfies the equation then it is a right triangle
if it does not then A^2 + B^2 > C^2 so it is acute triangle
if A^2 + B^2 < C^2 it is obtuse triangle

18^2 + 13^2 ? 27^2
324 + 169 ? 729
493 < 729 so it is obtuse triangle

3 0

3 years ago

What is the value of x HELPPPPPPPPPP PLZZZZZZZZZZZZ

natali 33 [55]

Answer:

Answer is D.

Step-by-step explanation:

all angles add up to 180(applys to triangles)

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2 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$