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pashok25 [27]
3 years ago
8

Hurry if correct I will give brainly ​

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

D

Step-by-step explanation:

A=20*20

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Which expression uses the associative property to make it easier to evaluate 14(3/2 x 1/4)
Sav [38]

Answer:

Not sure but the answer to 14(3/2 x 1/4) is 5.25

Step-by-step explanation:

6 0
3 years ago
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What is 77/200 as a decimal
AlladinOne [14]
The decimal for 77/200 is 0.385
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3 years ago
What is 1 2/3 multiplied by 4 1/2
horrorfan [7]
Change the mixed numbers into improper fractions:
5/3 X 9/2

Reduce - the 3 and 9 can be simplified
5/1 X 3/2

multiple numerators and denominators
15/2

Not sure how you need the answer - i would change it into a mixed number
7 1/2
3 0
3 years ago
Ms Hart had 40 dollars to spend on costume boxes for the musical. If she bought 12 boxes and received 4 dollars in change, how m
artcher [175]

Answer:each box cost =$3

Step-by-step explanation:

Amount of money Ms Hart has to spent on costume boxes=$40

Amount gotten as change after purchase=$4

Amount actually used up buying costume boxes =$40-$4=36

Since she bought 12 boxes , each box cost =$36/ 12=$3

5 0
3 years ago
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
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