Answer:
4 hours
Step-by-step explanation:
Given
Car 1:
Car 2:
--- i.e. 2 hours after car 1
Required
Determine the time car 1 will meet car 2
To do this, we calculate the distance of both cars using:
For Car 1:
For Car 2:
Open bracket
When car 2 meets up with car 1, they are at the same distance.
So:
Collect Like Terms
Solve for h
<em>Car 2 will catch car 1; 4 hours from the start</em>
Calculate R8 for f (x) =10−x
over [3,5]. Here is the solution:
R8 = ∫ [3..5] (10 - x) dx
= [ (50 - 25/2 ) - ( 30 - 9/2 ) ]
= ( 75/2 – 51/2 ) = 24/2
<span>= 12</span>
If sinα=1/4 and it is in q2 it means that the x coordinate is negative.
The triangle has a height of one and a hypotenuse of 4 so:
x=-√(4^2-1)
x=-√15
so tanα=-1/√15
tanα=-√(1/15)
tanα≈ -0.258
Answer:In geometry, the parallel postulate, also called Euclid's fifth postulate because it is the fifth postulate in Euclid's Elements, is a distinctive axiom in Euclidean geometry. It states that, in two-dimensional geometry
<em>y-intercept</em>
<em>y-interceptThe expression f(0) represents the y-intercept on the graph of f(x). The y-intercept of a graph is the point where the graph crosses the y-axis.</em>